If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-25x+46=0
a = 1; b = -25; c = +46;
Δ = b2-4ac
Δ = -252-4·1·46
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-21}{2*1}=\frac{4}{2} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+21}{2*1}=\frac{46}{2} =23 $
| x^-25x+46=0 | | x+4/x-1+x+7/x+1=6x+9/x^2-1 | | 2x2+9x=-10 | | 15=13z^-1-2z^-2 | | 11=x/13+4 | | |12-4x|-6=14 | | 5a2+4a=5 | | a/4-7=-8 | | -2-9b=70 | | 23=-3r+5 | | x÷-3=-7-3 | | 5-6k=11 | | 165=8m+5 | | a/15+6=7 | | -10n=2n-5 | | -8g+36=12 | | -117=-8x+3 | | v/18-4=-5 | | -81=6x-3(x+21) | | -37=-5-8x | | 7u−-3u=10 | | 3+y=68 | | |3x-3|9=0 | | 3=4+m/10 | | 4(x+2)-(4x+24)=0 | | 1.17−0.07a+(−3.92a)= | | 10z-16(200-z)-2z=0 | | 2x^2-59x-14=0 | | 7-7x-2=-21+5x-10 | | 38=8+2p | | 1/2(3b+8)+3/4=-1/2 | | 4x–4+x=5x-4 |